Chem Lab Help: How Do You Prepare 10.0 Kilograms Of 0.900% Saline Solution From A 9.00% Starting Solution?

Please be clear, this is my first time…

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2 Responses to “Chem Lab Help: How Do You Prepare 10.0 Kilograms Of 0.900% Saline Solution From A 9.00% Starting Solution?”

  1. Fortunately, you’ve got it in mass terms. This is a simple one. one Kg of
    9.0 % to 9 Kg of water gives 0.9% saline.
    .1 x 9% + .9 x 0% = 1 x 0.9%

  2. Do your % by mass.
    Step One
    =======
    Start with what you want.
    0.900 % of the solution means that 0.900% of the solution is salt.
    100% of the solution = 10 kg
    0.900% of the solution = x
    100x = 10*0.900
    100x = 9
    x = 9/100
    x = 0.09 kg
    Step Two
    =======
    Find out how much of the 9% saline solution you will use of the 9% starting solution.
    9% *x = 0.09 kg
    x = 0.09//9/100
    x = 0.01*100 = 1 kg
    Comment
    =======
    What this is telling you to do is to take 1 kg of the 9% solution and to that add 9 kg of water to the 1 kg.
    Does this not make sense to you? The %’s are related by a 10 to 1 ratio.